Exceeding maximum absolute voltage

"larry moe 'n curly" wrote in message
...
By how much can the maximum absolute voltage of 2.3V for DDR2 DRAM
chips be exceeded? I don't intend to do it, but I have a motherboard
that lets the memoy voltage be set as high as 2.839V, and it's maker
says that's OK, although they won't guarantee against damage.


By as much as you want!

For the most part though, voltage is directly related to temperature.
(simply ohms law) Increasing the voltage generally increases the core
temperature. The life expectancy decreases exponentially in many devices as
the voltage is increased past it's absolute maximums. The maximums also tend
to be "ideal"(hence the usage of absolute). Because of variations of
manufacturing, usage, etc, the maximums are a statistical result. Your usage
may vary.

"Jeff Johnson" wrote in
:

For the most part though, voltage is directly related to temperature.
(simply ohms law) Increasing the voltage generally increases the core
temperature.

Ohm's law has nothing to say about temperature!

While a resistance or voltage drop might vary with temperature, Ohm's law
does not deal with that.

"Jeff Johnson" wrote in
:

Increasing the voltage generally increases the core
temperature.

Which, because it deals with the increase in power, is actually Watt's law
(P=V/I), but that doesn't say anything about heat and temperature either.

Lostgallifreyan wrote:

"Jeff Johnson" wrote in
:

Increasing the voltage generally increases the core
temperature.

Which, because it deals with the increase in power, is actually Watt's law
(P=V/I), but that doesn't say anything about heat and temperature either.


P=V/I ?

That should turn up the heat....



mike

m II wrote in :

Lostgallifreyan wrote:

"Jeff Johnson" wrote in
:

Increasing the voltage generally increases the core
temperature.

Which, because it deals with the increase in power, is actually Watt's
law (P=V/I), but that doesn't say anything about heat and temperature
either.


P=V/I ?

That should turn up the heat....


Oh yeah, it would, wouldn't it?

P=V*I....