Floating point error?

The following C code:

float f = 5.15002;
double d = 5.15002;
if (d + FLT_EPSILON f)
puts("huh?");

Where 'FLT_EPSILON' is defined as the minimum number whereby 1.0 +
FLT_EPSILON != 1.0, causes the string "huh!" to be printed out on my
system (Pentium III)
I have included the relevant assembly code below.
Now is this a bug in the intel chip, or allowable because FLT_EPSILON
makes no promises when added to numbers greater than 1.0?

It doesn't happen when 'd' is another float, so presumably it has
something to do with double-precision/single-precision conversions
too.

Curious...

Dylan


8: float f = 5.15002;
00401028 C7 45 FC F7 CC A4 40 mov dword ptr [ebp-4],40A4CCF7h
9: double d = 5.15002;
0040102F C7 45 F4 D2 FB C6 D7 mov dword ptr
[ebp-0Ch],0D7C6FBD2h
00401036 C7 45 F8 9E 99 14 40 mov dword ptr [ebp-8],4014999Eh
10: if (d + FLT_EPSILON f)
0040103D DD 45 F4 fld qword ptr [ebp-0Ch]
00401040 DC 05 28 60 42 00 fadd qword ptr
[__real@8@3fe88000000000000000 (00426028)]
00401046 D9 45 FC fld dword ptr [ebp-4]
00401049 DE D9 fcompp
0040104B DF E0 fnstsw ax
0040104D F6 C4 41 test ah,41h
00401050 75 0D jne main+4Fh (0040105f)
11: puts("huh?");
00401052 68 1C 60 42 00 push offset string "huh?"
(0042601c)
00401057 E8 34 00 00 00 call puts (00401090)
0040105C 83 C4 04 add esp,4
12: return 0;
0040105F 33 C0 xor eax,eax

float f = 5.15002;
double d = 5.15002;
if (d + FLT_EPSILON f)
puts("huh?");

Where 'FLT_EPSILON' is defined as the minimum number whereby 1.0 +
FLT_EPSILON != 1.0, causes the string "huh!" to be printed out on my
system (Pentium III)
I have included the relevant assembly code below.
Now is this a bug in the intel chip, or allowable because FLT_EPSILON
makes no promises when added to numbers greater than 1.0?

It's allowable because FLT_EPSILON makes no promises when added to
numbers greater than 1.0.

Since this is an IEEE implementation with FLT_RADIX of 2, I'd expect
it to work
if (d + 4.0*FLT_EPSILON f)
puts("huh?");

for values of f where f = 4.0 and f 8.0 .

It doesn't happen when 'd' is another float, so presumably it has
something to do with double-precision/single-precision conversions
too.

Curious...

There is no exact representation of most non-integer decimal numbers
in binary floating point. This is the case for 5.15002 above.
You can't get an exact representation without an INFINITE number of
bits, but the more bits you use, the closer you'll get. Expect
double - float to lose accuracy. And don't think about "decimal digits".
0.1 in binary is an infinite repeating fraction.

Gordon L. Burditt

On 15 Jul 2003 19:25:24 -0700, (Dylan
Nicholson) wrote in comp.lang.asm.x86:

The following C code:

float f = 5.15002;
double d = 5.15002;
if (d + FLT_EPSILON f)
puts("huh?");

Where 'FLT_EPSILON' is defined as the minimum number whereby 1.0 +
FLT_EPSILON != 1.0, causes the string "huh!" to be printed out on my
system (Pentium III)
I have included the relevant assembly code below.
Now is this a bug in the intel chip, or allowable because FLT_EPSILON
makes no promises when added to numbers greater than 1.0?

It doesn't happen when 'd' is another float, so presumably it has
something to do with double-precision/single-precision conversions
too.

Curious...

Dylan

[snip]

You're misunderstanding the meaning of FLT_EPSILON.

If you want to check the minimum representable difference between the
float representation of 10.0 and the next higher float value, you need
to use FLT_EPSILON * 10. If you were checking a value around 100, you
would need to use FLT_EPSILON * 100.

--
Jack Klein
Home: http://JK-Technology.Com
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Jack Klein wrote:

On 15 Jul 2003 19:25:24 -0700, (Dylan
Nicholson) wrote in comp.lang.asm.x86:

The following C code:

float f = 5.15002;
double d = 5.15002;
if (d + FLT_EPSILON f)
puts("huh?");

Where 'FLT_EPSILON' is defined as the minimum number whereby 1.0 +
FLT_EPSILON != 1.0, causes the string "huh!" to be printed out on my
system (Pentium III)
I have included the relevant assembly code below.
Now is this a bug in the intel chip, or allowable because FLT_EPSILON
makes no promises when added to numbers greater than 1.0?

It doesn't happen when 'd' is another float, so presumably it has
something to do with double-precision/single-precision conversions
too.

Curious...

Dylan

[snip]

You're misunderstanding the meaning of FLT_EPSILON.

If you want to check the minimum representable difference between the
float representation of 10.0 and the next higher float value, you need
to use FLT_EPSILON * 10. If you were checking a value around 100, you
would need to use FLT_EPSILON * 100.

"close enough for government work" More accurately, FLT_EPSILON times the
largest integer power of FLT_RADIX which is less than the number to be
compared. 4*FLT_EPSILON in the case above. Not a good idea to redefine a
constant defined by Standard C, as the OP implies he is doing.
--
Tim Prince