(Nuno Magalhaes) wrote in message . com...
If you have a given sector, say 5000th sector (logical), how can you
get the physical location in: platters, tracks and sectors?

I've measured disk access times from sector 0 (track 0) to the start
of other tracks and got this results:

from to access time (ms)
0..126 - 1.3568 (track 3)
0..189 - 2.0449 (track 4)
0..252 - 2.7442 (track 5)
0..315 - 3.4373 (track 6)
0..378 - 4.1318 (track 7)
0..441 - 4.8222 (track 8)
0..504 - 5.5197 (track 9)
0..567 - 5.3046 (track 10)
0..630 - 4.6257 (track 11)
0..693 - 5.3169 (track 12)
0..756 - 6.0181 (track 13)
0..819 - 8.9897 (track 14)
0..882 - 9.6792 (track 15)
0..945 - 10.3711 (track 16)
0..1008 - 1.8192 (track 17)
0..1071 - 2.5135 (track 18)
0..1134 - 3.1956 (track 19)
0..1197 - 3.8969 (track 20)
0..1260 - 4.5939 (track 21)
0..1323 - 5.2856 (track 22)
0..1386 - 5.9845 (track 23)
0..1449 - 6.6760 (track 24)
0..1512 - 7.3691 (track 25)
0..1575 - 8.0571 (track 26)
0..1638 - 8.7536 (track 27)
0..1701 - 9.4473 (track 28)
0..1764 - 10.1306 (track 29)
0..1827 - 10.8335 (track 30)
0..1890 - 11.5330 (track 31)
0..1953 - 1.1275 (sometimes 12 ms) (track 32)
0..2016 - 3.6675 (track 33)

What should this mean? That there are 16 platters and the sectors are
enumerated from the inner cylinder to the outter cylinder?

Because I want to measure disk rotation times (to generate random
numbers according to a theorem) and this seems strange.